Webb9 feb. 2016 · y=1/4x-1+ln(2) First, find the point that the tangent line will intercept by plugging in x=4. y=ln(4/2)=ln(2) The point of tangency is (4,ln(2)). Differentiating y will be simpler if we make use of the following logarithm rule: ln(a/b)=ln(a)-ln(b) Thus, we can redefine the function as y=ln(x)-ln(2) When we differentiate this, recall that ln(2) is a … WebbQuestion: 47-48 Find an equation of the tangent line to the curve at the given point. 47. y=e2xcosπx,(0,1) 48. y=xex,(1,e) question 48 please! Show transcribed image text. Expert Answer. ... 47-48 Find an equation of the tangent line to the curve at the given point. 47. y …
What is the curve which passes through the point (1,1) and
Webb26 aug. 2024 · The point for the curve y= xe^x Advertisement sumit41520 is waiting for your help. Add your answer and earn points. Answer No one rated this answer yet — why not be the first? 😎 mkarpa001 Answer: (0,0) Step-by-step explanation: if X=0, y=0*e^0 =0 Find Math textbook solutions? Class 12 Class 11 Class 10 Class 9 Class 8 Class 7 Class 6 … WebbAI Recommended Answer: 1. Draw the x-axis and the y-axis. 2. Draw the first curve, y = 3xex2, on the x-axis. 3. Draw the second curve, y = 3ex, on the y-axis. 4. Find the point where the two curves intersect. 5. Draw the vertical line that connects the point where the two curves intersect to the origin. 6. bishops corner cafe bridgeport
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